Fungsi f: R->R dan g: R->R ditentukan oleh rumus f(x) = x+2 dan g(x) = 2x. Tentukanlah (f o g)^(-1) (x) dan (g o f)^(-1) (x) !

f(x) = x + 2
f⁻¹(x) = x - 2

g(x) = 2x
g⁻¹(x) = x/2

(f o g)⁻¹(x) = g⁻¹(x - 2)
= (x - 2) + 2
= x

(g o f)⁻¹(x) = f⁻¹(x/2)
= (x/2) - 2

f(x) = x + 2
g(x) = 2x

a) [tex]( f o g)^{-1} [/tex] = f (g(x) ) = (2x) + 2 kemudian diinvers
y = 2x + 2
[tex] x=\frac{y-2}{2} \\ y=\frac{x-2}{2}[/tex]

b) [tex]( g o f)^{-1} [/tex] = g (f(x) ) = 2 (x + 2) = 2x + 4 kemudian diinvers
y = 2x + 4
[tex] x=\frac{y-4}{2} \\ y=\frac{x-4}{2}[/tex]

Semoga Membantu ^^