Apa Penyelesain dari 3.|2×+3|=6

3|2x+3|=6
|2x+3| = 6-3
|2x+3| = 2
×(+) = 2x+3=2
2x = 2-3
2x = -1
x = -1/2
×(-) = -2x-3= 2
-2x = 2+3
-2x = 5
x = -5/2
HP {x|-5/2 atau -1/2,x anggota bilanga rasional}

Bab Nilai Mutlak
Matematika SMA Kelas X

3 |2x + 3| = 6
|2x + 3| = 6/3
|2x + 3| = 2

(2x + 3)² = 2²
(2x + 3)² - 2² = 0
(2x + 3 + 2) (2x + 3 - 2) = 0
(2x + 5) (2x + 1) = 0
2x + 5 = 0             atau              2x + 1 = 0
2x = -5                                       2x = -1
x = -5/2                                      x = -1/2

HP = { -5/2, -1/2 }