sebanyak 0,98 gram asam sulfat dalam 500 gram air hitunglah titik didih larutan jika kb air 5,2 dan mr h2so4 -98

delta Tb = kb.M.i
kb= 5,2
i = 1+(n-1) alfa
= 1+(3-1).1 = 3
jmlah mol= 0,98/98 = 0.01
M = 0.01/ 0.5 = 0.02

delta Tb = kb.M.i
= 5.2 x 0.02 x 3
= 0.312 drajat C
Tb = 100+ 0.312
= 100,312 °C