tolong yaaa kak.................... 2. BD = 4 cm AD = 4 cm AB = ....?

Kesebangunan

1)
PT = 6
TQ = 15
QR = 42
TS = 2x - 8

ΔPTS  sebangun Δ PQR
TS/QR = PT/PQ
TS/42 = 6 / (6 +15)
TS/42 = 6/ 21
TS = 42(6/21)
TS = 12
2x - 8 = 12
2x = 12 +8
2x = 20
x = 20/2
x = 10

2) Pitagoras
ΔABC siku siku di B
dan Δ ADB siku siku di D

AB² = AD² + DB²
AB² = 4² + 4²
AB² = 16 + 16
AB = √(16)(2)
AB = 4√2