pakai cara ... klau kelamaan dan udah tau jawabanya isiin aja langsung obsenya... jangan karuan

4][
cos 2x - sin x = 0
(1 - 2sin² x) - sin x = 0
(-2 sin x + 1)(sinx +1) = 0
sin x = 1/2 --> x = 30° (1/6 π) , 150° (5/6 π)
sin x = -1 --> x = 3/2 π

HP = {π/6 , 5π/6 , 3π/2}

0psi B

5][
1 + sin x = 3(1 - sin x)
sin x + 3 sin x = 3 - 1
4 sin x = 2
sin x = 1/2 --> x = 30° , x = 150°

Opsi C

4.
[tex]cos2x-sinx=0 \\ 1-2sin ^{2}x-sinx=0 \\ sinx=p \\ 2p ^{2}+p-1=0 \\ (p+1)(2p-1) =0 \\ \\ sinx=-1 \\ sinx=sin(- \frac{ \pi }{2}) \\ x=- \frac{ \pi }{2} +k.2 \pi \\ k=1,x= \frac{3}{2} \pi \\ \\ x= \frac{3}{2} \pi +k.2 \pi \\ k=0,x= \frac{3}{2 } \pi \\ \\ sinx= \frac{1}{2} \\ sinx=sin \frac{ \pi }{6} \\ x=\frac{ \pi }{6} +k.2 \pi \\ k=0,x= \frac{ \pi }{6} \\ \\ x= \frac{5}{6} \pi +k.2 \pi \\ k=0,x= \frac{5}{6} \pi \\ \\ Jawaban B \\ \\ \\ [/tex]

5.
[tex] \frac{1+sinx}{1-sinx} =3 \\ 1+sinx= 3-3sinx \\ 4sinx=2 \\ sinx= \frac{1}{2} \\ sinx=sin30 \\ \\ x= 30+k.360 \\ k=0,x= 30 \\ \\ x= 150+360 \\ k=0,x= 150\\ \\ JawabanC[/tex]