help me please............
Matematika
Septiantric
Pertanyaan
help me please............
1 Jawaban
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1. Jawaban Anonyme
TriGonoMetRi
sin x - √3 cos x = √2
k = √((-√3)² + 1²)
k = √4
k = 2
tan a = 1/-√3
tan a = -1/3 √3
a = 120° (sin (+) , cos (-))
sin x - √3 cos x = √2
k cos (x - a) = √2
2 cos (x - 120°) = √2
cos (x - 120°) = √2 /2
x - 120° = 45° atau x - 120° = 180° - 45°
x = 165° atau x = 255°
HP = {165° , 255°}