Tolong jawabkan dong

InTegraL

•
Misal :
u = 2x³ - 5
du/dx = 6x²
du = 6x² dx
2x² dx = 1/3 du

∫2x² /(2x³ - 5)^5/7 dx
= ∫u^-5/7 . 1/3 du
= 1/3 ∫u^-5/7 du
= 1/3 . 1/(2/7) . u^2/7 + C
= 7/6 . (2x³ - 5)^2/7 + C

Opsi : D

•
Misal :
u = 3x² + 9x - 1
du = (6x + 9) dx
du = 3(2x + 3) dx
(2x + 3) dx = 1/3 du

∫(2x + 3)/√(3x² + 9x - 1) dx
= ∫u^-1/2 . 1/3 du
= 1/3 . 1/(1/2) . u^1/2 + C
= 2/3 √(3x² + 9x - 1) + C

Opsi C