Tentukan hasil persamaan berikut 1. (2-3x) (5+2x)=0 2. X(x+4)=0 3. (3y+8)^2 =0 4. (3y+5) (y+2) =0 5. (y-4) (y-9) =0 Tolong dijawab ya saya ga ngerti cara g

1.
(2-3x) (5 +2x) = 0

2-3x = 0
-3x = -2
x = 2/3

dan

5 + 2x = 0
2x = -5
x = -5/2

2.
x(x + 4) = 0

x = 0

dan

x + 4 = 0
x = -4

3.
(3y+8)² = 0

3y + 8 = 0
3y = -8
y = -8/3

4.
(3y + 5) (y + 2) = 0

3y + 5 = 0
3y = -5
y = -5/3

dan

y + 2 = 0
y = -2

5.
(y - 4) (y - 9) = 0

y - 4 = 0
y = 4

dan

y - 9 = 0
y = 9