integral 9x^2 akar dari x^3+5 dx

= int (9x² √(x³ + 5) dx
= int (9x² (x³ + 5)^½ dx

u = x³ + 5
du = 3x² dx
3du = 9x² dx

= int u^½ 3du
= 3 int u^½ du
= 3/(½ + 1) u^(½ + 1) + c
= 3/(3/2) u^(3/2) + c
= 2u^(3/2) + c
= 2(x³ + 5)^3/2 + c
= 2√(x³ + 5)³ + c

semoga berguna +_+