Tentukan himpunan penyelesaian dari sistem persamaan linear 3 variabel berikut : 1. X+y+z=2 4x+2y+z=4 9x+3y+z=8 Tolong jawab ,please????

..x + ...y + z = 2
4x + 2y + z = 4
---------------------- -
-3x - y = -2 => pers.1

..x +... y + z = 2
9x + 3y + z = 8
---------------------- -
-8x - 2y = -6 => pers.2

pers.1 => -3x - y = -2 (× 2)
pers.2 => -8x - 2y = -6 (× 1)
-6x - 2y = -4
-8x - 2y = -6
------------------- -
2x = 2
x = 2/2
x = 1
-6x - 2y = -4
-6(1) - 2y = -4
-6 - 2y = -4
-2y = -4 + 6
-2y = 2
y = 2/-2
y = -1

x + y + z = 2
1 + (-1) + z = 2
1 - 1 + z = 2
0 + z = 2
z = 2

Jadi nilai x , y , dan z adalah {1 , -1 , 2}