Matematika

Pertanyaan

jika log 2=0,301,log 5=0,699. nikai daro log 5+log 8+log 125

1 Jawaban

  • log 5+log 8+log 125 = log(5 x 8 x 125) = log5000

    log5000 = log(1000 x 5)
                  = log1000 + log5
                  = 3 + 0,699
                  = 3,699
                                         

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