caranya kayak gimana??bantuin kerjain dong:( ((soalnya yg dilingkarin ya))

Uji kompetensi 1
1. 6x + 7 = 12
6x = 12 - 7
6x = 5
x = [tex]\frac{5}{6}[/tex] ... (d)

2. [tex]\frac{3x}{2}[/tex] + 5 = 9
[tex]\frac{3x}{2}[/tex] = 9 - 5
[tex]\frac{3x}{2}[/tex] = 4
3x = 4 x 2
3x = 8
x = [tex]\frac{8}{3}[/tex] = [tex]2\frac{2}{3}[/tex] ... (d)

3. 12 - [tex]\frac{5x}{6}[/tex] = 1
[tex]\frac{5x}{6}[/tex] = 12 - 1
[tex]\frac{5x}{6}[/tex] = 11
5x = 11 x 6
5x = 66
x = [tex]\frac{66}{5}[/tex] = [tex]13\frac{1}{3}[/tex] ... (d)

4. 3x + a = 15
jika x = 4, maka:
3(4) + a = 15
12 + a = 15
a = 15 - 12
a = 3 ... (e)

Uji kompetensi 2
1. 2x - 4 = 5x + 8
2x - 5x = 8 + 4
-3x = 12
x = [tex]\frac{12}{-3}[/tex]
x = -4 ... (a)

2. 2(x + 5) = 3(2x - 6)
2x + 10 = 6x - 18
6x - 2x = 18 + 10
4x = 28
x = [tex]\frac{28}{4}[/tex]
x = 7 ... (e)

3. [tex]\frac{x+2}{3}[/tex] = 5 - [tex]\frac{x}{2}[/tex]
[tex]\frac{x+2}{3}[/tex] + [tex]\frac{x}{2}[/tex] = 5
[tex]\frac{2(x+2)}{6}[/tex] + [tex]\frac{3(x)}{6}[/tex] = 5
[tex]\frac{2x+4}{6}[/tex] + [tex]\frac{3x}{6}[/tex] = 5
[tex]\frac{2x+4+3x}{6}[/tex] = 5
2x + 4 + 3x = 30
5x + 4 = 30
5x = 30 - 4
5x = 26
x = [tex]\frac{26}{5}[/tex] = [tex]5\frac{1}{5}[/tex] ... (e)

uji kompetensi 3
1. [tex]\frac{3}{2x}[/tex] = [tex]\frac{1}{x-2}[/tex]
3(x - 2) = 1(2x)
3x - 6 = 2x
3x - 2x = 6
x = 6 ... (e)

2. [tex]\frac{4}{x-3}[/tex] = [tex]\frac{2}{x+1}[/tex]
4(x + 1) = 2(x - 3)
4x + 4 = 2x - 6
4x - 2x = - 4 - 6
2x = - 10
x = [tex]\frac{-10}{2}[/tex] = -5 ... (a)

3. [tex]\frac{2}{x+1}[/tex] - [tex]\frac{1}{x}[/tex] = [tex]\frac{4}{x}[/tex]
[tex]\frac{2}{x+1}[/tex] = [tex]\frac{4}{x}[/tex] + [tex]\frac{1}{x}[/tex]
[tex]\frac{2}{x+1}[/tex] = [tex]\frac{5}{x}[/tex]
2(x) = 5(x + 1)
2x = 5x + 5
2x - 5x = 5
-3x = 5
x = [tex]\frac{5}{-3}[/tex] = - [tex]1\frac{2}{3}[/tex] ... (a)