Matematika

Pertanyaan

tolong yaa kak...............

26. AD = 15 cm.
tolong yaa kak............... 26. AD = 15 cm.

1 Jawaban

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    25)
    EA(EB) = ED(EC)
    18(3) = ED (9)
    ED = 18(3) / 9
    ED = 6

    26.
    AF  = AB (AD) / BD)
    AF = 20(15)/(25)
    AF = 12

    BF² = AB² - AF²
    BF² = 20² - 12² = 400 - 144 = 256
    BF = 16

    FD = BD - BF
    FD = 25 - 16
    FD = 9

    FD² = AF x FE
    9² = 12 x FE
    FE = 81/12 = 6, 75

    AE = AF + FE
    AE = 12 + 6,75
    AE = 18,75

    Luas trapesium ABED  = luas ΔADE + Luas ΔABE
    Luas ABED =  1/2 AE . FD  + 1/2 .AB. AD
    Luas ABED = 1/2  ( AE .FD + AB. AD)
    Lua ABED = 1/2 (18,75 x 9  + 20 x 15)
    Luas ABED = 1/2 (168.75 + 300) = 1/2 (468,75)
    Luas ABED = 234, 375  atau 234, 4 cm²

    27. ABCD adalah  layang layang
    AB = AD = 6
    BC = CD = 8
    AC² = AD² + CD² = 6² +8² = 100
    AC = 10

    BD  = 2 DE
    BD = 2 (AD x CD/ AC)
    BD  = 2 (6x 8)/10
    BD  = 96/10
    BD = 9,6 cm
    DE tegak lurus A