besok aku uts plis bantu ya ... integral dr sin (5x-4)dx apaaa?

[tex] \int\limits sin{(5x - 4)} \, dx [/tex]
misal u = 5x - 4, du = 5 dx, 1/5 du = dx

[tex] \int\limits \frac{1}{5} sin u \, du \\ \\ \frac{1}{5} \int\limits sin u \, du \\ \\ \frac{1}{5}. - cos u + c \\ \\ -\frac{1}{5}.cos(5x - 4) + c [/tex]

[tex]\int \sin(5x-4) dx \\ u=5x-4 \\ du=5 $ dx, maka $dx=\frac{du}{5} \\ \int 1.\sin(5x-4)dx \\ \int \frac{1}{5} \sin(u) du \\ -\frac{1}{5}\cos(u)+C \\ -\frac{1}{5}\cos(5x-4)+C[/tex]