kerucut pelukis 25 luas selimut 550 brp volumenya

Materi : Bangun Ruang

Pembahasan :
Luas Selimut Kerucut = 550
22/7 . r . 25 = 550
550/7 r = 550
r = 7 cm

Volume = 1/3 πr²t
Volume = 1/3(22/7)(7)²(25)
Volume = 1283,33 cm³

Dik : Luas selimut kerucut 550 cm² , Garis pelukis 25 cm. π=22/7
Dit : Volume Kerucut.. ?
Jawaban :
Luas selimut kerucut = π.r.s = 22/7.r.25
550=550/7.r
r =3850 : 550 = 7 cm.
:") Tinggi kerucut = √625 - √49 = √576 = 24 cm.
Jadi, volume kerucut = 1/3.π.r².t
= 1/3. 22/7. 7². 24 = 1.22.49.24/3.7 = 25872 : 21 = 1232 cm³.