metode substitusi 2x-3y=5 dan 3x+2y=1

Metode subtitusi

2x - 3y = 5
2x = 5 + 3y
x = (5 + 3y)/2

3x + 2y = 1
3(5 + 3y)/2 + 2y = 1 ------ (×2)
3(5 + 3y) + 4y = 2
15 + 9y + 4y = 2
13y = 2 - 15
y = -13 : 13
y = -1

x = (5 + 3y)/2
x = (5 + 3.(-1) / 2
x = (5 - 3) / 2
x = 2 / 2
x = 1

HP {1 , -1}

Semoga berguna +_+