X²-4=0 (rumus ABC) tolong d jwb mmkai rumus ABC

Materi : Persamaan Kuadrat

Pembahasan :
x² - 4 = 0

a = 1 ; b = 0 : c = -4

D = b² - 4ac
D = 0² - 4(1)(-4)
D = 16

X1 = (-b + √D)/2a
X1 = (-0 + √16)/2.1
X1 = 4/2
X1 = 2

X2 = (-b - √D)/2a
X2 = (-0 - √16)/2.1
X2 = -4/2
X2 = -2

Hp : {-2 , 2}