x2+4x-12 per 2x kuadrat+9x-18 mohon jawaban nya + cara nya ya

= [tex] \frac{ x^{2} + 4x - 12}{ 2x^{2} +9x-18} [/tex]
= [tex] \frac{(x+6)*(x-2)}{(2x-3)*(x+6)} [/tex]
= [tex] \frac{x-2}{2x-3} [/tex]