Matematika

Pertanyaan

nilai x dari akar 8 pangkat x-5 = 4 pangkat 4+2x

2 Jawaban

  • 8 ^(x-5) = 4 ^(4+2x)
    Samakan bilangan pokok
    A^b = A^c
    .b =c
    2^((3(x-5)) = 2^((2(4+2x))
    ((3(x-5)) = ((2(4+2x))
    3x-15 =8+4x
    3x-4x = 8+15
    -x = 23
    .x =-23
  • √8∧(x-5) = 4∧(4+2x)
    (2∧3/2)∧ (x-5) = (2∧2)∧(4+2x)
    2∧(3/2 x - 15/2) = 2∧(8+4x)


    3/2 x - 15/2 = 8+4x
    3/2 x - 4x = 8+15/2
    -2 1/2 x = 31/2
    -5/2 x = 31/2
    x = -31/5
    x = -6 1/5

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