Nilai x yang memenuhi persamaan : [tex] \frac{4}{5}(2 ^{3x-2}) + \frac{8 ^{x} }{20} } = 1 [/tex] adalah .................... ( pakai rumus yang gampang paham ya

4/5 (2^(3x - 2)) + 8^x /20 = 1
4/5 (2^x)^3 . 1/2^2 + (2^x)^3 /20 = 1
▶ Misal : 2^x = a
a³/5 + a³/20 = 1
(4a³ + a³)/20 = 1
5a³ = 20
a³ = 20/5
a³ = 4
a = (2^2)^1/3
2^x = 2^2/3
x = 2/3