Gradien melalui titik (-2,1) dan (6,3)
Matematika
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Pertanyaan
Gradien melalui titik (-2,1) dan (6,3)
2 Jawaban
-
1. Jawaban idznizhahrina
m= (y2-y1)/(x2-x1)
= (3-1)/(6-(-2))
= 2/8
= 1/4 -
2. Jawaban arsetpopeye
(-2, 1) = (x1, y1)
(6, 3) = (x2, y2)
gradien (m) = (y2 - y1)/(x2 - x1)
= (3 - 1)/(6 - (-2))
= 2/8
= 1/4