selesesaikan persamaaneksponen berikut! 2^2x+3 . 7^-2x=28

2^(2x+3) . 7^(-2x)=28
2^(2x+3) . 7^(-2x) = 2^2 x 7

2x+3=2
2x=2-3
2x=-1
x=-1/2

2^(2x + 3) . 7^(-2x) = 28
2^(2x + 3) . 7^(-2x) = 4 . 7
2^(2x + 3) . 7^(-2x) = 2^2 . 7^1

1) 2^(2x + 3) = 2^2
=> 2x + 3 = 2
=> 2x = -1
=> x = -1/2

2) 7^(-2x) = 7^1
=> -2x = 1
=> x = -1/2