selesaikan persamaan trigonometri tan 2 A+ tan A= 0, dengan 0 derajat < A< 180 derajat.. Tolong di jwab ya kak?

tan(2a)=tan(a)/(1-tan^2(a))

misalin tan(a)=x

x/(1-x^2)+x=0
x(1+1/(1-x,^2))=0
x=0, tan(a)=0, a=0, 180

1+1/(1-x^2)=0
1/(1-x^2)=-1
1=-(1-x^2)
x^2-1=1
x^2-2=0
x=√2, tan(a)=√2, a=arctan(√2)
x=-√2, tan(a)=-√2, a=arctan(-√2)