tentukan titik didih larutan urea (Mr=60) jika diketahui kadar 1,2% dan kb air =0,52

dik :Mr=60
kadar=1,2%
kb=0,52
dit : Tb
jawab
m urea=1,2/100.100%=1,2gram
m air=100-1,2=98,8gram

ΔTb = [massa urea/Mr] x [1000/massa air] x Kb
ΔTb = [1,2/60] x [1000/98,8]x 0,52
Kenaikan titik didih = ΔTb = 0,105 C
∴ Titik didih larutan = 100+ 0,105 = 100,105°C