jika log2 = 0,30 log3 = 0,477 maka : a.log 60 b log 9/8 c log akar 2/3 d log 12
Matematika
junaidiusman977
Pertanyaan
jika log2 = 0,30
log3 = 0,477
maka : a.log 60
b log 9/8
c log akar 2/3
d log 12
log3 = 0,477
maka : a.log 60
b log 9/8
c log akar 2/3
d log 12
1 Jawaban
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1. Jawaban Matrixisme
b. log[tex]\frac{9}{8}[/tex] = log9 - log8 = log[tex]3^{2}[/tex] - log[tex]2^{3}[/tex] = 2 log3 - 3 log2 = 2(0,477) - 3(0,30) = 0,954 - 0,9 = 0,054
c. log[tex]\sqrt{\frac{2}{3}}[/tex] = log[tex]\frac{2}{3}^{\frac{1}{2}}[/tex] = [tex]\frac{1}{2}[/tex] log[tex]\frac{2}{3}[/tex] = [tex]\frac{1}{2}[/tex](log2 - log3) = [tex]\frac{1}{2}[/tex](0,30 - 0,477) = [tex]\frac{1}{2}[/tex] x (- 0,177) = -0,0885
d. log 12 = log(2 x 2 x 3) = log2 + log2 + log3 = 0,30 + 0,30 + 0,477 = 1,077