Kimia

Pertanyaan

hitung fraksi mol dari larutan urea 30% Mr urea=60 Mr air = 18!

1 Jawaban

  • Kita menganggap kalau 100% = 100 gr

    Massa urea = 30% = 30 gr (Mr=60)
    Massa air = 100%-30% = 70% = 70 gr (Mr=18)
    x ...?

    nt = gr/Mr = 30/60 = 0,5
    np = gr/Mr = 70/18 = 3,88

    xUrea = nt/np+nt
    xUrea = 0,5/0,5+3,88
    xUrea = 0,5/4,388
    xUrea = 0,114

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