(akar6+akar3) (2akar 3-akar6)

(√6+√3)(2√3-√6)
=√6.2√3-√6.√6+√3.2√3-√3.√6
=2√18-6+2.3-√18
= 2√(2.9)-6+6-√(2.9)
= 2.3√2-3√2
=6√2-3√2
= 3√2

Aljabar

= (√6 + √3)(2√3 - √6)
= 2√18 - √36 + 2√9 - √18
= 2√(9×2) - 6 + 2.3 - √(9×2)
= 2.3√2 - 6 + 6 - 3√2
= 6√2 - 3√2
= (6 - 3)√2
= 3√2

Semoga berguna +_+