Jika 2 log 7 = p, nilai 14 log 98??

[tex]^2log 7 = p \\ \\ ^{14}log 98= \frac{^2log(2.7^2)}{^2log(2.7)} \\ \\ = \frac{^2log2+^2log7^2}{^2log2+^2log7} \\ \\ = \frac{1+2p}{1+p} [/tex]