itu gimana ya yg no 7

2^x/8^(x+2)=64*√(2^(3x))*√(8^(3x))
misal u=8^x
u^(1/3)/(2^6*)u=2^6*u^(1/2)*u^(3/2)
u^(-2/3)=2^12*u^2
u^(-8/3)=2^12
8^(-8x/3)=2^12
2^(3*-8x/3)=2^12
2^-8x=2^12
-8x=12
x=-3/2

mohon maaf apabila ada kesalahan